Our method for finding probabilities for normal distribution problems will be as follows:
EXAMPLE:\
Let X be the blood platelet count (measured in thousands per cc of
blood) in humans, and suppose
. What is the
probability that an individual has a platelet count between 185.4 and
360.2? It is a good idea to always draw a picture. The solution is as
follows. We have
is given by
which, in turn is P(-1.96<Z<1.96), which is
We might also ask what the value of X is equivalent to the 99% percentile (99% of all individuals will have a platelet count below this value). To solve this we reverse the process used above:
which means that
Thus, someone with a blood-platelet count of 376.72 has a higher count than 99% of the population.