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Finding Areas and Quantiles for Z Curve

Our method for finding probabilities for normal distribution problems will be as follows:

EXAMPLE:\ Let X be the blood platelet count (measured in thousands per cc of blood) in humans, and suppose tex2html_wrap_inline3545 . What is the probability that an individual has a platelet count between 185.4 and 360.2? It is a good idea to always draw a picture. The solution is as follows. We have

displaymath3547

is given by

displaymath3549

which, in turn is P(-1.96<Z<1.96), which is

displaymath3553

We might also ask what the value of X is equivalent to the 99% percentile (99% of all individuals will have a platelet count below this value). To solve this we reverse the process used above:

From the Z table, we find that z=2.33 has area to the left of 0.99. Now using the equation for Z we get

displaymath3571

which means that

displaymath3573

Thus, someone with a blood-platelet count of 376.72 has a higher count than 99% of the population.



Jan Lethen
Wed Nov 13 16:20:46 CST 1996